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Mike1975 · 05-16-2018, 07:28 AM

It's a simple punnett square
https://en.m.wikipedia.org/wiki/Punnett_square

DD + Dd
a non carrier (DD) + a carrier of the recessive (Dd)

50% Dd
50% DD

If both parents are carriers there is 25% chance of a non carrier puppy.

If both parents have expressed the dilution gene, meaning they are both (dd), then all the resulting puppies will be (dd) as they (the parents) don't have the dominant D to pass it to their offspring.

DD + dd
All puppies will be carriers of the recessive (d)

05-16-2018, 07:28 AM	#39
Mike1975 Senior Yorkie Talker Join Date: May 2012 Location: Athens, Greece Posts: 174	It's a simple punnett square https://en.m.wikipedia.org/wiki/Punnett_square DD + Dd a non carrier (DD) + a carrier of the recessive (Dd) 50% Dd 50% DD If both parents are carriers there is 25% chance of a non carrier puppy. If both parents have expressed the dilution gene, meaning they are both (dd), then all the resulting puppies will be (dd) as they (the parents) don't have the dominant D to pass it to their offspring. DD + dd All puppies will be carriers of the recessive (d) Last edited by Mike1975; 05-16-2018 at 07:33 AM.