Quote:
Originally Posted by concretegurl  I see, and as such then that entire line carries for the blue born, and thus the line should be ended no? |
Yes. If it cannot be determined genetically by DNA analysis that a pup has 2 dominant genes instead of 1 dominant and 1 recessive, then I wouldn't want to breed that pup due to the possibilities...which would definitely mean that ANY of Sasha's previous pups might be a carrier. I mentioned Sasha's previous stud because if the OP did not know about this stud...who was being used and was a carrier...there is increased likelihood that Sasha's previous stud might have been, also. There is also increased likelihood that the rest of Sasha's pups from this breeding that produced the blue born have at least 1 carrier among them. The kind thing to do is pass the information on to any known to have acquired an unaltered Sasha pup, and especially so if they acquired the unaltered pup with intent to breed.
It's kind of 'math meets statistics' with genetics...lol. To understand better, if you search for "Punnett Square" you can easily see how it happens. I discovered this in 7th grade and used to build huge Punnett Squared to work in church...it kept me still and quiet, and has fascinated me to this day...really got interesting when I began to study dilute calico cat genetics. lol
Basically, it looks like this (without the actual box grid), using "
G" as the dominant gene and "
g" as the recessive gene...pups 1, 2, 3 and the blue born pup 4 represented in the middle:
Stud (Across)
Gg Stud 1 Stud 2
Sasha (Down)
Gg G g
Sasha 1
G GG Gg g Gg gg