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Originally Posted by Limelitediva  This is easily explicable! Both of your yorkie parents are CARRIERS of dominant and recessive traits. This is called heterozygous. To be heterozygous means to have one dominent and one recessive allel given. Each allel is passed on by the parents of the pups. Therefore each pup can have a different geneotypic ratio which expresses different phenotypes. The different combinations for lets say a silky coated pup from two heterozygous parents can be SS (which is silky), Ss (which is silky), sS (which is silky), or ss (which is wirey). The reason for this is as long as a dominant trait (S) is given to the puppy the puppy will have a silky coat. If the puppy obtained both (s) then the puppys coat will be wirey.  |
My understanding from what I've read is that a dog that displays a trait known to be recessive had to have inherited this gene from both parents and would therefore be homozygous for that trait, for example, two partis producing only partis. So how could two dogs that both exhibit the trait of a recessive gene produce other than that trait unless that trait is governed by more than one pair of genes?
I will say that both the sire and dam I mentioned in an earlier post do have long silky coats but both exhibit a slight bit of waviness along the hindquarters. The pups from the first litter show no hint of waviness in their coats. I did keep a girl from that litter but have not bred her yet so am unsure of what to expect. My thought is that if I use a male with a fully straight coat that I would see the pups have straight coats.