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Old 02-26-2008, 09:14 PM   #7
Tillys_mom
Spoilin' Tilly & Jack
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Join Date: Feb 2006
Location: Indiana
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Originally Posted by Tillys_mom View Post
My hubby said this....

first get the original equation into the form y=mx+b with m being the slope of the line and b being the y intercept. To do this solve the original equation for y. The equation in this form will then look like y=-1/2x+4. When 2 lines are perpendicular the slopes when multiplied together equal -1. Since the slope of your original line is -1/2 the slope of the new line is 2. Then to determine the y intercept of the new line you will use the point which the line passes through (1,-6) and the slope, which was 2. Plug 1 in for x, -6 in for y and 2 in for m in y=mx+b. B with then be equal to -4. Therefore the equation for the new line will be y=2x-4. Then put this equation back into standard form by getting both the x and y terms on the same side of the equation, it will then look like, 2x-y=4.
He said you may wanna double check to see if he screwed up. LOL
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