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mistyinca · 10-09-2007, 06:45 PM

tee hee...I had to pull out the formula to see how it works

[250(80x+1) + y + y -250]/2

=(20000x + 250 + 2y - 250)/2

=(20000x + 2y)/2

=(20000x)/2 + 2y/2

=10000x + y

Basically you're just multiplying the first three digits of your phone number by 10000 and adding the last 4.

(who says there isn't a purpose for algebra!)

10-09-2007, 06:45 PM	#145
mistyinca No Longer a Member Join Date: Jan 2007 Location: USA Posts: 4,143 Blog Entries: 2	tee hee...I had to pull out the formula to see how it works [250(80x+1) + y + y -250]/2 =(20000x + 250 + 2y - 250)/2 =(20000x + 2y)/2 =(20000x)/2 + 2y/2 =10000x + y Basically you're just multiplying the first three digits of your phone number by 10000 and adding the last 4. (who says there isn't a purpose for algebra!)